# calculateAge.js (8kyu 95)

#### Problem

• Your task is to write a function that takes two parameters: the year of birth and the year to count years in relation to.
• 출생연도부터 해당연도까지 계산하는 함수를 작성한다.

#### Solution 01

``````function calculateAge(birthYear, currentYear) {
let age = currentYear - birthYear;

if (age === 1) return 'You are 1 year old.';
else if (age === -1) return 'You will be born in 1 year.';
else if (age > 0) return `You are \${age} years old.`;
else if (age < 0) return `You will be born in \${-age} years.`;
else return 'You were born this very year!';
}

calculateAge(1988, 1988);  // You were born this very year!
calculateAge(1988, 1989);  // You are 1 year old.
calculateAge(1988, 2019);  // You are 31 years old.
calculateAge(1988, 1987);  // You will be born in 1 year.
calculateAge(2030, 2019);  // You will be born in 11 years.
``````

#### Solution 02

``````function calculateAge(birthYear, currentYear) {
let year = Math.abs(birthYear - currentYear) === 1 ? 'year' : 'years';

if (birthYear === currentYear) return 'You were born this very year!';
if (birthYear < currentYear) return `You are \${currentYear - birthYear} \${year} old.`;
if (birthYear > currentYear) return `You will be born in \${-currentYear + birthYear} \${year}.`;
}

calculateAge(1988, 1988);  // You were born this very year!
calculateAge(1988, 1989);  // You are 1 year old.
calculateAge(1988, 2019);  // You are 31 years old.
calculateAge(1988, 1987);  // You will be born in 1 year.
calculateAge(2030, 2019);  // You will be born in 11 years.
``````

`Math.abs()` 메소드

주어진 숫자의 절대값(absolute value)을 반환한다.

` 오 많 배`